Scotsville tote - please explain

Horse no 3 pays 0 for win and place, yet there is money in the pool

1  Alan's Pride 3.50 5.50  
2  I Have Wings SCR SCR 
3 Client King 0.00 0.00 
4 Obama Way 34.90 4.10 
5 Robyn's Man 1.40 4.30 
6 Polarity 0.00 0.60 
7 Swift Arrow 36.80 34.00 
8 Outback King 13.20 2.50 
9 Full Of Dreams 6.60 0.80 
10 Beware The Queen SCR SCR 
11 Hit A High SCR SCR 

 

NETT POOLS

WN  961
PL 328
SW  130
TF  201
EX  104
QT  247
DD  40
P3 150
JP  1688
P6  5388
PA  4209

 

 

Probably no tickets on. So dividing by zero gives you a NaN or not-a-number as far a computer goes.

When do the tote pools open?

Surely if there is no ticket on no 3, the full pool of R961must be displayed as the win amount?
If the horse won, surely the full amount of R961will be carried forward?
not clever enough to follow the computer programmers logic?
perhaps there are a few of these type of programming features?

There would have been no tickets on the runner at that stage.

It can't display R961. That means that R1 was placed on the runner. Just as if someboby put R10 and it would have displayed R96.

I agree that it must show 0. Remember the displayed price is not showing the pool, put the pool divided by the tickets on the runners. If it Won a paid R0 i.e no winners then the pool will get carried over.